3.239 \(\int \frac {x^3}{(a-b x^2)^3} \, dx\)

Optimal. Leaf size=20 \[ \frac {x^4}{4 a \left (a-b x^2\right )^2} \]

[Out]

1/4*x^4/a/(-b*x^2+a)^2

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Rubi [A]  time = 0.00, antiderivative size = 20, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.071, Rules used = {264} \[ \frac {x^4}{4 a \left (a-b x^2\right )^2} \]

Antiderivative was successfully verified.

[In]

Int[x^3/(a - b*x^2)^3,x]

[Out]

x^4/(4*a*(a - b*x^2)^2)

Rule 264

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[((c*x)^(m + 1)*(a + b*x^n)^(p + 1))/(a
*c*(m + 1)), x] /; FreeQ[{a, b, c, m, n, p}, x] && EqQ[(m + 1)/n + p + 1, 0] && NeQ[m, -1]

Rubi steps

\begin {align*} \int \frac {x^3}{\left (a-b x^2\right )^3} \, dx &=\frac {x^4}{4 a \left (a-b x^2\right )^2}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 25, normalized size = 1.25 \[ -\frac {a-2 b x^2}{4 b^2 \left (a-b x^2\right )^2} \]

Antiderivative was successfully verified.

[In]

Integrate[x^3/(a - b*x^2)^3,x]

[Out]

-1/4*(a - 2*b*x^2)/(b^2*(a - b*x^2)^2)

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fricas [A]  time = 0.96, size = 38, normalized size = 1.90 \[ \frac {2 \, b x^{2} - a}{4 \, {\left (b^{4} x^{4} - 2 \, a b^{3} x^{2} + a^{2} b^{2}\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3/(-b*x^2+a)^3,x, algorithm="fricas")

[Out]

1/4*(2*b*x^2 - a)/(b^4*x^4 - 2*a*b^3*x^2 + a^2*b^2)

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giac [A]  time = 0.62, size = 26, normalized size = 1.30 \[ \frac {2 \, b x^{2} - a}{4 \, {\left (b x^{2} - a\right )}^{2} b^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3/(-b*x^2+a)^3,x, algorithm="giac")

[Out]

1/4*(2*b*x^2 - a)/((b*x^2 - a)^2*b^2)

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maple [A]  time = 0.01, size = 35, normalized size = 1.75 \[ \frac {a}{4 \left (b \,x^{2}-a \right )^{2} b^{2}}+\frac {1}{2 \left (b \,x^{2}-a \right ) b^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3/(-b*x^2+a)^3,x)

[Out]

1/4*a/b^2/(b*x^2-a)^2+1/2/b^2/(b*x^2-a)

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maxima [A]  time = 1.31, size = 38, normalized size = 1.90 \[ \frac {2 \, b x^{2} - a}{4 \, {\left (b^{4} x^{4} - 2 \, a b^{3} x^{2} + a^{2} b^{2}\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3/(-b*x^2+a)^3,x, algorithm="maxima")

[Out]

1/4*(2*b*x^2 - a)/(b^4*x^4 - 2*a*b^3*x^2 + a^2*b^2)

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mupad [B]  time = 0.04, size = 37, normalized size = 1.85 \[ -\frac {\frac {a}{4\,b^2}-\frac {x^2}{2\,b}}{a^2-2\,a\,b\,x^2+b^2\,x^4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3/(a - b*x^2)^3,x)

[Out]

-(a/(4*b^2) - x^2/(2*b))/(a^2 + b^2*x^4 - 2*a*b*x^2)

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sympy [B]  time = 0.27, size = 36, normalized size = 1.80 \[ - \frac {a - 2 b x^{2}}{4 a^{2} b^{2} - 8 a b^{3} x^{2} + 4 b^{4} x^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3/(-b*x**2+a)**3,x)

[Out]

-(a - 2*b*x**2)/(4*a**2*b**2 - 8*a*b**3*x**2 + 4*b**4*x**4)

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